$(2+4x)(2-4x) = $   ?

$4 \,- 16\,x^2$ $2 \,- 16\,x^2$ $4\, +16\,x\,+ 16\,x^2$ $4\, -16\,x\,+ 16\,x^2$

$(2x-10)^2 = $   ?

$4\,x^2\, -40\,x\,+ 100$ $4\,x^2\, -20\,x\,+ 100$ $4\,x^2\, -40\,x\,+ 10$ $2\,x^2\, -40\,x\,+ 100$

$(4y-5)^2 = $   ?

$16\,y^2\, -40\,y\,+ 25$ $16\,y^2\, -20\,y\,+ 25$ $16\,y^2\, -40\,y\,+ 10$ $4\,y^2\, -40\,y\,+ 25$

$(-3y+10x)(-3y-10x) = $   ?

$-6\,y^2 \,- 100\,x^2$ $9\,y^2 \,- 20\,x^2$ $9\,y^2 \,- 100\,x^2$ $9y \,- 100\,x^2$

$(-5y+5x)^2 = $   ?

$25\,y^2\, -50\,x\,y\,+ 5\,x^2$ $25\,y^2\, -50\,x\,y\,+ 25\,x^2$ $25\,y^2\, +50\,x\,y\,+ 25\,x^2$ $-25\,y^2\, -50\,x\,y\,+ 25\,x^2$

$(2x+3)^2 = $   ?

$2\,x^2\, +12\,x\,+ 9$ $4\,x^2\, +12\,x\,+ 9$ $4\,x^2\, +12\,x\,+ 3$ $4\,x^2\, -12\,x\,+ 9$