$\dfrac{19}{3}\times\dfrac{2}{11}$ =

$\dfrac{10}{3}\times\dfrac{7}{4}$ =

$11 \times\dfrac{14}{77}$ =

$\dfrac{1}{4}\times\dfrac{17}{3}$ =

$\dfrac{23}{19}\times\dfrac{5}{10}$ =

$\dfrac{2}{3}\times\dfrac{23}{13}$ =

$\dfrac{-5}{3}\times\dfrac{5}{-7}$ =

$7 \times\dfrac{-21}{49}$ =

$\dfrac{1}{4}\times 17$ =

$\dfrac{2}{11}\times\dfrac{4}{6}$ =