$ \,3\,x - \,2\,\,x^2 - ( - \,4\,\,x^2 + \,8\,x )=$ ?

$\,6\,\,x^2 \,-5\,x$ $\,-6\,\,x^2 +\,11\,x$ $\,2\,\,x^2 +\,11\,x$ $\,-6\,\,x^2 \,-5\,x$ $\,2\,\,x^2 \,-5\,x$

$\,4\,x + (\,1 - \,2\,x + \,6\,y) =$ ?

$\,6\,x +\,6\,y +\,1$ $\,2\,x +\,6\,y +\,1$ $\,2\,x \,-6\,y +\,1$ $\,-2\,x +\,6\,y \,-1$ $\,6\,x \,-6\,y \,-1$

$\,6\,x - ( - \,3\,\,x^2 - \,1 ) + \,x=$ ?

$\,-3\,\,x^2 +\,7\,x \,-1$ $\,3\,\,x^2 +\,7\,x +\,1$ $\,-3\,\,x^2 +\,7\,x +\,1$ $\,3\,\,x^2 +\,7\,x \,-1$ $\,3\,\,x^2 +\,5\,x +\,1$

$ \,5\,\,x^2 - ( \,8 + \,7\,\,x^2 + \,x)=$ ?

$\,-2\,\,x^2 \,-\,x \,-8$ $\,12\,\,x^2 +\,x +\,8$ $\,-2\,\,x^2 +\,x +\,8$ $\,-2\,\,x^2 +\,x \,-8$ $\,12\,\,x^2 \,-\,x \,-8$

$ \,4\,x + \,7\,y - ( \,6\,x - \,4\,y)=$ ?

$\,-2\,x +\,3\,y$ $\,10\,x +\,3\,y$ $\,10\,x +\,11\,y$ $\,-2\,x +\,11\,y$ $\,-2\,x \,-3\,y$

$\,3 + ( - \,7\,x + \,5) - ( \,3 - \,6\,x) =$ ?

$\,x +\,3$ $\,-13\,x +\,5$ $\,-\,x +\,5$ $\,-\,x +\,11$ $\,-\,x \,-5$