$\dfrac{7}{6}\times\dfrac{35}{10}$ =

$\dfrac{11}{5}\times\dfrac{3}{4}$ =

$\dfrac{19}{3}\times\dfrac{2}{13}$ =

$\dfrac{21}{19}\times\dfrac{9}{6}$ =

$\dfrac{7}{6}\times\dfrac{11}{10}$ =

$13 \times\dfrac{9}{39}$ =

$\dfrac{-1}{14}\times\dfrac{23}{-2}$ =

$\dfrac{10}{4}\times\dfrac{7}{3}$ =

$15 \times\dfrac{7}{-35}$ =

$\dfrac{3}{38}\times 7$ =