$\dfrac{21}{2}\times\dfrac{3}{8}$ =

$\dfrac{3}{11}\times\dfrac{17}{6}$ =

$7 \times\dfrac{21}{49}$ =

$\dfrac{5}{38}\times 3$ =

$-10 \times\dfrac{19}{38}$ =

$\dfrac{-2}{7}\times\dfrac{3}{-7}$ =

$\dfrac{7}{2}\times\dfrac{11}{3}$ =

$\dfrac{9}{7}\times\dfrac{5}{6}$ =

$\dfrac{7}{3}\times\dfrac{21}{6}$ =

$\dfrac{7}{5}\times\dfrac{3}{11}$ =