$\dfrac{3}{34}\times 11$ =

$\dfrac{2}{5}\times\dfrac{3}{11}$ =

$\dfrac{8}{13}\times\dfrac{14}{6}$ =

$\dfrac{5}{3}\times\dfrac{6}{9}$ =

$25 \times\dfrac{7}{35}$ =

$\dfrac{-5}{7}\times\dfrac{-3}{7}$ =

$\dfrac{33}{2}\times\dfrac{3}{19}$ =

$\dfrac{7}{8}\times\dfrac{15}{9}$ =

$7 \times\dfrac{21}{-49}$ =

$\dfrac{13}{2}\times\dfrac{3}{19}$ =